Geometry Problem Solver

Parallelepiped and cylinder together

parallelepiped	cylinder

Parallelepiped alone

Cylinder alone

They give the tracks some problems can be solved automatically, the numerical values do not matter in the various examples. Only the problems already tested are reported. In fact, the problems solved by the geometric computer, but not tested, with a parallelepiped and cylinder together, are about 2 x 200 problems on parallelepiped x 80 problems on cylinder = 32,000

Track 1

The basic circumference of a cylinder is 36 π cm and the total cylinder area is 864 π cm². Calculates the height of a parallelepiped equivalent to the cylinder and having the base area equal to 1/3 of the lateral area of the cylinder.

Track 2

The basic circumference of a cylinder is 36 π cm and the total cylinder area is 864 π cm². Calculates the volume of a parallelepiped with a base area of 600 cm² and a height congruent to 1/3 of the height of the cylinder.

Track 3

The basic circumference of a cylinder is 36 π cm and the total cylinder area is 864 π cm². Calculates the volume of a parallelepiped having the base area of 600 cm² and the height equal to the height of the cylinder.

Track 4

A parallelepiped has a base sizes of 24 cm and 18 cm and a height of 50 cm. Calculates the height of a congruent cylinder to 3/2 of the parallelepiped and having the base area congruent to 3/4 of the lateral area of the parallelepiped.

Track 5

A parallelepiped has a base size of 24 cm and 18 cm and a height of 50 cm. Calculates the volume of a cylinder having the base area congruent to 3/4 of the total area of the parallelepiped and the height of 30 cm.

Parallelepiped alone

Cylinder alone